Aptitude quiz aptitude quiz online
1.The simple interest on a sum of money is 4/9 of the principal .Find the time, if rate percent and time both are numerically equal.
Let sum = Rs. x. Then, S.l. = Rs. 4x/9
Let rate = R% and time = R years.
Then, (x*R*R)/100=4x/9 or R2 =400/9 or R = 20/3 = 6 2/3.
Rate = 6 2/3 % and Time = 6 2/3 years = 6 years 8 months.
2. A certain sum of money amounts to Rs. 1008 in 2 years and to Rs.1164 in 3 ½ years. Find rate of interest.
S.I. for 1 ½ years = Rs.(1164-1008) = Rs.156.
S.l. for 2 years = Rs.(156*(2/3)*2)=Rs.208
Principal = Rs. (1008 - 208) = Rs. 800.
Now, P = 800, T = 2 and S.l. = 208.
Rate =(100* 208)/(800*2)% = 13%
3. The difference between the compound interest and the simple interest accrued on an amount of Rs. 18,000 in 2 years was Rs. 405. What was the rate of interest p.c.p.a. ?
Rate = 15%
Let the rate be R% p.a. then,
[ 18000 ( 1 + ( R / 100 )2 ) - 18000 ] - ((18000 * R * 2) / 100 ) = 405
18000 [ ( 100 + (R / 100 )2 / 10000) - 1 - (2R / 100 ) ] = 405
18000[( (100 + R )2 - 10000 - 200R) / 10000 ] = 405
9R2 / 5 = 405
R2 =((405 * 5 ) / 9) = 225
R = 15. Rate = 15%.
4. The sum of a rational number and its reciprocal is 13/6. Find the number.
Answer : x = 2/3 or x = 3/2
5. Find a number such that when 15 is subtracted from 7 times the number, the Result is 10 more than twice the number.
Let the number be x.
Then, 7x - 15 = 2x + 10 => 5x = 25 =>x = 5.
Hence, the required number is 5.
6. A sum of Rs. 800 amounts to Rs. 920 in 8 years at simple intere interest rate is increased by 8%, it would amount to bow much ?
S.l. = Rs. (920 - 800) = Rs. 120;
p = Rs. 800, T = 3 yrs.
R = ((100 x 120)/(800*3) ) % = 5%.
New rate = (5 + 3)% = 8%.
New S.l. = Rs. (800*8*3)/100 = Rs. 192.
New amount = Rs.(800+192) = Rs. 992.
7. If the simple interest on a sum of money at 5% per annum for 3 years is Rs. 1200, find the compound interest on the same sum for the same period at the same rate.
Clearly, Rate = 5% p.a., Time = 3 years, S.I.= Rs. 1200.
So principal=RS [100*1200]/3*5=RS 8000
Amount = Rs. 8000 x [1 +5/100]^3 - = Rs. 9261
C.I. = Rs. (9261 - 8000) = Rs. 1261.
8. One side of a rectangular field is 15 m and one of its diagonals is 17 m. Find the area of the field.
Other side = ((17) 2- (15)2)(1/2) = (289- 225)(1/2) = (64)(1/2) = 8 m
Area = (15 x 8) m2 = 120 m2.
9. Find the compound interest on Rs. 10,000 in 2 years at 4% per annum, the interest being compounded half-yearly.
Principal = Rs. 10000; Rate = 2% per half-year
Time = 2 years = 4 half-years.
Amount = Rs [10000 * (1+(2/100))4] = Rs(10000 * (51/50) * (51/50) * (51/50) * (51/50)) = Rs. 10824.32.
:. C.I. = Rs. (10824.32 - 10000) = Rs. 824.32.
10. Find the simple interest on Rs. 3000 at 6 1/4% per annum for the period from 4th Feb., 2005 to 18th April, 2005.
Time = (24+31+18)days = 73 days = 73/365 years = 1/5 years.
P = Rs.3000 and R = 6.25%p.a = 25/4%p.a
S.I. = Rs.(3,000*(25/4)*(1/5)*(1/100))= Rs.37.50
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