Online Free Aptitude test 2020| Aptitude Quiz
Free Aptitute test
1. The difference of two numbers is 11 and one-fifth of their sum is 9. Find the numbers.
Let the number be x and y. Then,
x - y = 11 ----(1) and 1/5 (x + y) = 9 => x + y = 45 ----(2)
Adding (1) and (2), we get: 2x = 56 or x = 28. Putting x = 28 in (1), we get: y = 17.
Hence' the numbers are 28 and 17.
2. Divide Rs. 1301 between A and B, so that the amount of A after 7 years is equal to the amount of B after 9 years, the interest being compounded at 4% per annum.
Let the two parts be Rs. x and Rs. (1301 - x).
x(1+4/100)7 =(1301-x)(1+4/100)9
x/(1301-x)=(1+4/100)2=(26/25*26/25)
625x=676(1301-x)
1301x=676*1301
x=676.
So,the parts are rs.676 and rs.(1301-676)i.e rs.676 and rs.625.
3. The product of the ages of Ankit and Nikita is 240. If twice the age of Nikita is more than Ankit's age by 4 years, what is Nikita's age?
Let Ankit's age be x years. Then, Nikita's age = 240/x years.
2*(240 /x ) - x = 4
480 - x2 = 4x
x2 + 4x - 480 = 0
(x+24)(x-20) = 0
x = 20.
Hence, Nikita's age = 12 years.
4. One year ago, the ratio of Gaurav's and Sachin's age was 6: 7 respectively. Four years hence, this ratio would become 7: 8. How old is Sachin ?
Let Gaurav's and Sachin's ages one year ago be 6x and 7x years respectively.
Then, Gaurav's age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachin's age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
(6x+5)/(7x + 5) = 7/8
8(6x+5) = 7(7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachin's present age = (7x + 1) = 36 years.
5. The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
Let the son's present age be x years.
Then, father's present age = (3x + 3) years
(3x + 3 + 3) = 2 (x + 3) + 10
3x + 6 = 2x + 16
x = 10.
Hence, father's present age = (3x + 3) = ((3*10) + 3) years = 33 years.
6. The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.
Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
3 (x - 6) = (x + 16 - 6)
3x -18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years.
7. Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev ?
Let Rajeev's present age be x years. Then,
Rajeev's age after 15 years = (x + 15) years.
Rajeev's age 5 years back = (x - 5) years.
x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeev's present age = 10 years.
8. If the sum of two numbers is 42 and their product is 437, then find the absolute difference between the numbers.
Let the numbers be x and y. Then,
x + y = 42 and xy = 437
x- y = sqrt[(x + y)2 - 4xy] = sqrt[(42)2 - 4 x 437 ] = sqrt[1764 - 1748] = sqrt[16] = 4.
Required difference = 4.
9. A number is as much greater than 36 as is less than 86. Find the number.
Let the number be x. Then,
x - 36 = 86 - x
2x = 86 + 36 = 122
x = 61.Hence, the required number is 61.
10. In a stream running at 2kmph,a motar boat goes 6km upstream and back again to the starting point in 33 minutes.find the speed of the motarboat in still water.
let the speed of the motarboat in still water be x kmph.then,
6/x+2 +6/x-2=33/60
11x2-240x-44=0
11x2-242x+2x-44=0
(x-22)(11x+2)=0
x=22.
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