TIME AND DISTANCE QUIZ 2020

1. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

A) 7.2
B) 10
C) 8.4
D) 3.6

... Answer is A)
Explanation: Speed = 600/ 5 x 60 m/sec. = 2 m/sec. = 2 x 18/5km/hr =7.2 km/hr

2. An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of

A) 360 kmph
B) 600 kmph
C) 720 kmph
D) 300 kmph

... Answer is C)
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr.
Required speed = 1200 x 3/5km/hr = 720 km/hr.

3. A car covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of car will have to increase?

A) 40km/hr
B) 60km/hr
C) 90km/hr
D) 120km/hr

... Answer is D)
Explanation:
Initial speed = 80km/hr
Total distance = 80 * 10 = 800km
new speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr

4. A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?

A) 3 1/5 Km
B) 2 1/5 Km
C) 4 1/5 Km
D) 5 1/5 Km

... Answer is A)
Explanation:
S1×S2/S2-S1 × T1+T2/60
= 4×6/2 × 16/6
= 24/2 × 16/60
= 8 × 2/5
= 16/5 = 3 1/5 Km

5. An express train travelled at an average speed of 100 km/hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point?

A) 6 hrs 21 min
B) 6 hrs 24 min
C) 6 hrs 30 min
D) 6 hrs 27 min

... Answer is A)
Explanation:
Time taken to cover 600 km = (600/100)hrs =6 hrs.
Number of stoppages = 600/75 - 1 =7.
Total Time of stoppages= (3 x 7)min=21 min.
Hence, total time taken=6 hrs 21 min.

6. Two trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?

A) 11:9
B) 7:3
C) 18:4
D) None of thesewrong

... Answer is A)
Explanation:
In the same time, they cover 110 km and 90 km respectively.
For the same time, speed and distance is inversely proportional.
So ratio of their speed = 110:90 = 11: 9

7. Walking at the rate of 4 kmph a man cover a certain distance in 2 hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in.

A) 50 min
B) 12 min
C) 40 min
D) 60 min

... Answer is C)
Explanation:
Distance = Speed × time
Here time = 2hr 45 min = 11/4 hr
Distance = 4×11/4=11 km
New Speed =16.5 kmph
Therefore time = D/S=11/16.5=40 min

8. Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance?

A) 1 hr 42 min
B) 1 hr
C) 2 hr
D) 1 hr 12 min

... Answer is D)

Explanation:
New speed =6/7 of usual speed
Speed and time are inversely proportional.
Hence new time =7/6 of usual time
Hence, 7/6 of usual time - usual time =12 minutes
⇒1/6 of usual time =12 minutes
Therefore, usual time =12×6=72 minutes=1 hour 12 minutes

9. The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours?

A) 456 km
B) 482 kmwrong
C) 558 km
D) 552 kmcorrect

... Answer is D)

Explanation:
Total distance travelled in 12 hours =(35+37+39+.....upto 12 terms)
This is an A.P with first term, a=35, number of terms,
n= 12,d=2.
Required distance = 12/2[2 x 35+{12-1) x 2]
=6(70+23)
= 552 kms.

10. A runner can complete a 750 m race in two and a half minutes. Will he be able to beat another runner who runs at 17.95 km/hr?

A) Yes
B) No
C) Insufficient Data
D) None

... Answer is D)
Explanation:
We are given that the first runner can complete a 750 m race in 2 minutes and 30 seconds or 150 seconds.
=> Speed of the first runner = 750 / 150 = 5 m / sec
We convert this speed to km/hr by multiplying it by 18/5.
=> Speed of the first runner = 18 km / hr
Also, we are given that the speed of the second runner is 17.95 km/hr.
Therefore, the first runner can beat the second runner.